[分享]：关于把金额转换成大写技巧集萃

快乐219

假设A1单元格为原始数据

一、公式法一：
=IF(A1=0,"零元整",IF(A1<0,"负",)&IF(INT(ABS(A1)),TEXT(INT(ABS(A1)),"[dbnum2]")&"元",)&IF(INT(ABS(A1)*10)-INT(ABS(A1))*10,TEXT(INT(ABS(A1)*10)-INT(ABS(A1))*10,"[dbnum2]")&"角",IF(INT(ABS(A1))=ABS(A1),,"零"))&IF(ROUND(ABS(A1)*100-INT(ABS(A1)*10)*10,),TEXT(ROUND(ABS(A1)*100-INT(ABS(A1)*10)*10,),"[dbnum2]")&"分","整"))

二、公式法二：
=IF(A1<0,"负",)&TEXT(TRUNC(ABS(A1)),"[DBNum2]G/通用格式")&"元"&IF(ROUND(A1,3)=ROUND(A1,),"整",TEXT(RIGHT(TRUNC(A1*10),1),"[DBNum2]G/通用格式")&"角"&IF(ROUND(A1,3)=ROUND(A1,1),"整",TEXT(RIGHT(ROUND((A1*100),),1),"[DBNum2]G/通用格式")&"分"))

三、公式法三：
=CONCATENATE(TEXT(INT(A1),"[DBNum2][$-804]G/通用格式")&"元"&IF((INT(A1*10)-INT(A1)*10)=0,"",TEXT(IF(AND(CEILING(A1*100,1)-INT(A1*10)*10=10,INT(A1*1000)-INT(A1*100)*10>=5),INT(A1*10)-INT(A1)*10+1,INT(A1*10)-INT(A1)*10),"[DBNum2][$-804]G/通用格式")&"角")&IF(OR(INT(A1*100)-INT(A1*10)*10=0,(IF(INT(A1*1000)-INT(A1*100)*10>=5,CEILING(A1*100,1)-INT(A1*10)*10=10,FALSE))),"整",(IF(INT(A1*1000)-INT(A1*100)*10>=5,(IF(CEILING(A1*100,1)-INT(A1*10)*10=10,"",(TEXT(CEILING(A1*100,1)-INT(A1*10)*10,"[DBNum2][$-804]G/通用格式")&"分"))),(TEXT(INT(A1*100)-INT(A1*10)*10,"[DBNum2][$-804]G/通用格式")&"分")))),"(￥",FIXED(A1,2,TRUE),"元)")

四、VBA代码法（自定义函数）
Public Function BigNum(xiaoxie As Currency)
  Application.Volatile
  Dim fuhao As String
  
  fuhao = ""
  
  If xiaoxie < 0 Then
  xiaoxie = -xiaoxie
  fuhao = "负"
  End If
  
  If xiaoxie = 0 Then
    BigNum = "零元整"
  Else
    Const cNum = "零壹贰叁肆伍陆柒捌玖-万仟佰拾亿仟佰拾万仟佰拾元角分"
    Const cCha = "零仟零佰零拾零零零零零亿零万零元亿万零角零分零整-零零零零零亿万元亿零整整"
    BigNum = ""
    sNum = Trim(Str(Int(Round(xiaoxie, 2) * 100)))
      For i = 1 To Len(sNum)
        BigNum = BigNum + Mid(cNum, (Mid(sNum, i, 1)) + 1, 1) + Mid(cNum, 26 - Len(sNum) + i, 1)
      Next i
      For i = 0 To 11
        BigNum = Replace(BigNum, Mid(cCha, i * 2 + 1, 2), Mid(cCha, i + 26, 1))
      Next i
      BigNum = fuhao + BigNum
   End If
End Function

上面四种办法中，方法一和方法四等价；方法二、三和方法一、四的区别只是整数部分为零时，方法一、四不显示“零元”，而直接显示“角分”；方法三在方法2的基础上加上了数字显示，下面是不同数据在四种方法中的显示结果：
原始数据 方法一 方法二 方法三 方法四
0.12 壹角贰分 零元壹角贰分 零元壹角贰分(￥0.12元) 壹角贰分
1.02 壹元零贰分 壹元零角贰分 壹元贰分(￥1.02元) 壹元零贰分
1001001 壹佰万壹仟零壹元整 壹佰万壹仟零壹元整 壹佰万壹仟零壹元整(￥1001001.00元) 壹佰万壹仟零壹元整
0 零元整 零元整 零元整(￥0.00元) 零元整
-25001 负贰万伍仟零壹元整 负贰万伍仟零壹元整 -贰万伍仟零壹元整(￥-25001.00元) 负贰万伍仟零壹元整
这个功能更强大、全面下面是转的其他朋友的VBA作品，功能更为强大：
Public Function AAA(number As Variant) As String
   If (IsNull(number)) Then
      AAA = "错误：传入负值或Null值"
   Else
      Select Case number
         Case 0: AAA = "零"
         Case 1: AAA = "壹"
         Case 2: AAA = "贰"
         Case 3: AAA = "叁"
         Case 4: AAA = "肆"
         Case 5: AAA = "伍"
         Case 6: AAA = "陆"
         Case 7: AAA = "柒"
         Case 8: AAA = "捌"
         Case 9: AAA = "玖"
         Case 10 ^ 1: AAA = "分"
         Case 10 ^ 2: AAA = "角"
         Case 10 ^ 3: AAA = "元"
         Case 10 ^ 4, 10 ^ 8, 10 ^ 12: AAA = "拾"
         Case 10 ^ 5, 10 ^ 9, 10 ^ 13: AAA = "佰"
         Case 10 ^ 6, 10 ^ 10, 10 ^ 14: AAA = "仟"
         Case 10 ^ 7: AAA = "萬"
         Case 10 ^ 11: AAA = "亿"
      End Select
   End If
End Function

Public Function abc(number As Variant, canshu As Long) As String
   Dim C, D, Y, X, Z As String
   Dim A, b, k

   A = Int(number * 100 + 0.5)
   b = Len(CStr(A))
   D = CStr(A)
   If (b > 14) Then MsgBox "数字过大无法转换": Exit Function
   If (number < 0) Then MsgBox "错误：不可传入负值": Exit Function
   If A = 0 Then abc = "": Exit Function
   For k = 1 To b
      Select Case canshu
         Case 1
            Y = AAA(Mid(D, b - k + 1, 1)) + AAA(10 ^ k)
            Select Case k
               Case 1
                  If Mid(D, b, 1) = "0" Then C = "整" Else C = Y + C
               Case 2, 4, 5, 6, 8, 9, 10, 12, 13, 14
                  If Mid(D, b - k + 1, 2) = "00" Then C = C _
                  Else: _
                  If Mid(D, b - k + 1, 1) = "0" And Mid(D, b - k + 2, 1) <> "0" Then _
                  C = "零" + C Else: C = Y + C
               Case 7
                  If b >= 11 Then
                     If Mid(D, b - k - 2, 4) = "0000" Then
                        C = C
                     Else
                        If Mid(D, b - k + 1, 1) = "0" And Mid(D, b - k + 2, 1) = "0" _
                        Then C = AAA(10 ^ k) + C _
                        Else: If Mid(D, b - k + 1, 1) = "0" And Mid(D, b - k + 2, 1) <> "0" _
                        Then C = AAA(10 ^ k) + "零" + C Else: C = Y + C
                     End If
                  Else
                     If Mid(D, b - k + 1, 1) = "0" And Mid(D, b - k + 2, 1) = "0" _
                     Then C = AAA(10 ^ k) + C _
                     Else: If Mid(D, b - k + 1, 1) = "0" And Mid(D, b - k + 2, 1) <> "0" _
                     Then C = AAA(10 ^ k) + "零" + C Else: C = Y + C
                  End If
               Case 3, 11
                  If Mid(D, b - k + 1, 1) = "0" And Mid(D, b - k + 2, 1) = "0" _
                  Then C = AAA(10 ^ k) + C _
                  Else: If Mid(D, b - k + 1, 1) = "0" And Mid(D, b - k + 2, 1) <> "0" _
                  Then C = AAA(10 ^ k) + "零" + C Else: C = Y + C
            End Select
         Case 2
            C = AAA(Mid(D, b - k + 1, 1)) + " " + C
         Case 3
            C = AAA(Mid(D, b - k + 1, 1)) + AAA(10 ^ k) + C
      End Select
   Next
   abc = C
End Function

161433

啊~~