[求助]：应用acedCommand执行open操作？

MiracleMark

想通过编程实现自动打开已经存在的dwg文档，代码如下：

acedCommand(RTSTR, "FILEDIA", RTSTR, "0", RTNONE);//系统变量FILEDIA设为0，执行open命令不显示对话框
acedCommand(RTSTR, "OPEN", RTSTR, "c:\a.dwg", RTNONE);//执行Open

acedCommand(RTSTR, "FILEDIA", RTSTR, "1", RTNONE);//系统变量FILEDIA设为1，执行open命令显示对话框

但AutoCAD似乎不接受OPEN后面的变量值"c:\a.dwg",而认为"c:\a.dwg"是一个系统命令，请问这个该如何解决？

另外有没有更好的方法在多文档模式下实现自动打开指定路径的文件呢？

用appContextOpenDocument也不行，求教高手！谢谢

xysyr

AcApDocManager::sendStringToExecute Function virtual Acad::ErrorStatus

sendStringToExecute(

AcApDocument* pAcTargetDocument,

const char * pszExecute,

bool bActivate = true,

bool bWrapUpInactiveDoc = false,

bool bEchoString = true) = 0;

pAcTargetDocument Document to send input to
pszExecute String to use as input
bActivate Boolean indicating whether to activate the target document
bWrapUpInactiveDoc Boolean indicating whether to queue current active document to complete in next OnIdle() when switching active documents.
bEchoString Boolean indicating whether the sent string is echoed on the command line

This function sends a string to the command line to be executed in the provided target document.

MiracleMark

to xysyr：
按sendStringToExecute执行命令和acedCommand的结果一样，仍然是执行到open的时候停下来了
        AcApDocument *pDoc = acDocManager->curDocument();
        rc = acDocManager->sendStringToExecute(pDoc,"FILEDIA\n");
        rc = acDocManager->sendStringToExecute(pDoc,"0\n");
        rc = acDocManager->sendStringToExecute(pDoc,"open\n");
        //rc = acDocManager->sendStringToExecute(pDoc,"C:\\AutoCAD\\打印图.dwg\n");
        rc = acDocManager->sendStringToExecute(pDoc,"FILEDIA\n");
        rc = acDocManager->sendStringToExecute(pDoc,"1\n");
截张图上来可以看到，没有执行参数"C:\\AutoCAD\\打印图.dwg\n"

MiracleMark

按esc取消，可看到open命令后面似乎不接受参数，和filedia命令不同，郁闷，不知道该如何让open 命令能够直接接收指定路径的文件名

cutechun

acDocManager->appContextOpenDocument("c:\\a.dwg");

MiracleMark

调用这个函数，好像只能在非模态对话框中使用；其它的模态对
话框中或者是不使用mfc调用，总是没法调用成功，返回值是eNotApplicable，是不是acDocManager->appContextOpenDocument("c:\\a.dwg");只适用于非模态对话框？