[ARX程序]：求一个点

bluesolar

AcGeVector3d v,vzix;
AcGeVector3d v1(pt1-pt2);
AcGeVector3d v2(pt3-pt2);
v1.normalize();
v2.normalize();
v=v1+v2;//角平分线；
vzix.set(0,0,1);
double anglea,angleb,anglec;
anglea=v2.angleTo(v1,vzix);
AcGeLine3d vLine(pt2,v);
现在想求沿v方向、距pt2为len的点以及v与X轴的夹角，该怎么办呢？
谢谢！

XDSoft

很多时候，不用向量，使用ARX全局函数，更方便

你试试：

void
acutPolar(
    const ads_point pt,
    ads_real angle,
    ads_real dist,

    ads_point result)

Include File

acutads.h

Finds a point by means of polar coordinates.
Sets result to the point that is at angle and dist from the initial point pt. The pt and result arguments are three-dimensional points. The angle is expressed in radians, measured from the X axis with the value increasing in the counterclockwise direction.
The acutPolar() function does not return a value.

sv300

pt=pt2+v*len