图块位置不变的情况下重设块的插入点

LoveArx

Resetting the origins of block table records in a drawing

Issue
I have a drawing that contains block table records with non-zero origins, i.e.
they are not set to (0, 0, 0). How can I reset these origins without moving the
positions of all the block's sub-entities in the drawing?

Solution
The following code demonstrates how to modify a block table record's
origin and compensate by moving the insertion point of each of the associated
block references.

Please add the function 'testFunc' as a command.

1. void ResetAllInstances(AcDbBlockTableRecord * pBlockTableRecord, AcGeVector3d &translation)
   
2. {
   
3. 
   
4. // Note that this function does not implement any error checking.
   
5. // We are assuming that pBlockTableREcord was opened for write by the calling function
   
6. 
   
7. // Iterate through all block references of this block table record.
   
8. AcDbBlockReferenceIdIterator * pIterator;
   
9. pBlockTableRecord->newBlockReferenceIdIterator(pIterator);
   
10. for (pIterator->start();!pIterator->done();pIterator->step())
    
11. {
    
12.   AcDbBlockReference * pBlockRef;
    
13.   pIterator->getBlockReference(pBlockRef, AcDb::kForWrite,true);
    
14. 
    
15.   // Transform the translation vector from block coordinates to world coordinates.
    
16.   AcGeVector3d realTranslation = (pBlockRef->blockTransform())*translation;
    
17. 
    
18.   // Translate the block reference to counter the effect of the origin change.
    
19.   pBlockRef->setPosition(pBlockRef->position()+realTranslation);
    
20. 
    
21. 
    
22.   pBlockRef->close();
    
23. } // Next block reference
    
24. delete pIterator;
    
25. }
    

void ResetAllInstances(AcDbBlockTableRecord * pBlockTableRecord, AcGeVector3d &translation)<br /> {<br /> <br /> // Note that this function does not implement any error checking.<br /> // We are assuming that pBlockTableREcord was opened for write by the calling function<br /> <br /> // Iterate through all block references of this block table record.<br /> AcDbBlockReferenceIdIterator * pIterator;<br /> pBlockTableRecord->newBlockReferenceIdIterator(pIterator);<br /> for (pIterator->start();!pIterator->done();pIterator->step())<br /> {<br />   AcDbBlockReference * pBlockRef;<br />   pIterator->getBlockReference(pBlockRef, AcDb::kForWrite,true);<br /> <br />   // Transform the translation vector from block coordinates to world coordinates.<br />   AcGeVector3d realTranslation = (pBlockRef->blockTransform())*translation;<br /> <br />   // Translate the block reference to counter the effect of the origin change.<br />   pBlockRef->setPosition(pBlockRef->position()+realTranslation);<br /> <br /> <br />   pBlockRef->close();<br /> } // Next block reference<br /> delete pIterator;<br /> }<br />

下面是测试命令SGP

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819534890

学习学习学习

qq1254582201

看看怎么样，貌似不错的样子啊

qq1254582201

不太懂arc，完全蒙了不明觉厉的感觉

牢固

回复学习

lijun126136

很好，谢谢分享

ARX2014

我也来学习学习

zjy2999

学习！！！！！！！！！！！！！

lennie

btrbtrbtrbtr

lionguns

学习！！！！！！！！！！！！！！！！！！！！！

1425361224

我来学习学习是怎么回事？

开水瓶游泳

RE: 图块位置不变的情况下重设块的插入点 [修改]

edata

啥也不说了，感谢楼主分享哇！

QiaoCheng

谢谢分享，回复学习

ssyfeng

我写的块会变位置