[求助]：求一画相贯线切口形状程序

lzws03

这阵子做管桁架工程较多，出详图时需要画两管相贯的切口形状。我发现有人的随便画了个圆弧就放到那里，我看着不太舒服，但我也没有太简便的方法。所以我想请大家帮忙做一个绘制相贯切口的程序。
在MSTOOLS工具箱中有这个功能，不过它绘制出来的有些不太真实，与实际展出来的不一样，我想找一个能绘制这种切口的，最好能当做实际放样线做成样板后拿到车间就能用的程序。
如果多管相贯比较麻烦，那么大家能不能先做一个两管相贯且没有偏心的程序先试一试？

zxq0220

程序
[php]
(DEFUN C:XGX ()
(SETQ OLDOS (GETVAR "OSMODE"))
(SETVAR "OSMODE" 0)
(SETVAR "CMDECHO" 0)
(SETQ D (GETDIST "\nDiamter of D = ")
      DS (GETDIST "\nDiamter of d = "))
(WHILE (> DS D)
(PROMPT "\nThe d must less than D! ")
(SETQ DS (GETDIST "\nDiamter of d= "))
)
(SETQ B (GETREAL "\nAngle of the pipe (DEG) B= <90> "))
(WHILE (= B 0)
(PROMPT "\nThe angle B must begger than 0")
(SETQ B (GETREAL "\nAngle of the pipe (DEG) B= <90> "))
)
(SETQ B (/ (* (IF (= B nil) 90 0) PI) 180)
      ANG (- B PI)
      A 0 TA (/ (* 5 PI) 180)
      RS (* DS 0.5) R (* D 0.5)
      PT (GETPOINT "\nPipe Conect Point : ")
      PT1 (POLAR PT 0 (/ RS (SIN B))))
(IF (EQUAL D DS 1E-5) (PROGN
(SETQ PT2 (POLAR PT ANG (/ RS (SIN B))) PT3 (POLAR PT PI (/ RS (SIN B))))
(COMMAND "PLINE" PT1 PT2 PT3 "")
) (PROGN
(SETQ A (+ A TA) RA (* (SIN A) RS) RB (* (COS A) RS))
(COMMAND "PLINE" PT1 "A")
(SETQ PT2 (POLAR (POLAR PT 0 (/ RB (SIN B))) ANG (/ (- R (SQRT (- (* R R) (* RA RA)))) (SIN B))))
(COMMAND "S" PT2)
(REPEAT 35
  (SETQ A (+ A TA) RA (* (SIN A) RS) RB (/ (* (COS A) RS) (SIN B))
        PT2 (POLAR (POLAR PT 0 RB) ANG (/ (- R (SQRT (- (* R R) (* RA RA)))) (SIN B))))
  (COMMAND PT2)
)
(COMMAND "")
))
(SETVAR "OSMODE" OLDOS)
(SETVAR "CMDECHO" 1)
(PRINC)
)
[/php]

lzws03

楼上兄，以下是我的意见反馈。

;;;
命令: xgx
Diamter of D = 350

Diamter of d = 200

Angle of the pipe (DEG) B= <90> 36.5

Pipe Conect Point : ; 错误: 除数为零

命令:

;;;

我的操作过程是把您的程序拷贝到记事本里，然后存为LSP格式加载到CAD中，然后运行XGX程序就出现了以上的结果。解决办法？？

zxq0220

写错一个地方，下面是更改后的程序：
[php]
(DEFUN C:XGX ()
(SETQ OLDOS (GETVAR "OSMODE"))
(SETVAR "OSMODE" 0)
(SETVAR "CMDECHO" 0)
(SETQ D (GETDIST "\nDiamter of D = ")
      DS (GETDIST "\nDiamter of d = "))
(WHILE (> DS D)
(PROMPT "\nThe d must less than D! ")
(SETQ DS (GETDIST "\nDiamter of d= "))
)
(SETQ B (GETREAL "\nAngle of the pipe (DEG) B= <90> "))
(WHILE (= B 0)
(PROMPT "\nThe angle B must begger than 0")
(SETQ B (GETREAL "\nAngle of the pipe (DEG) B= <90> "))
)
(SETQ B (/ (* (IF (= B nil) 90 B) PI) 180)
      ANG (- B PI)
      A 0 TA (/ (* 5 PI) 180)
      RS (* DS 0.5) R (* D 0.5)
      PT (GETPOINT "\nPipe Conect Point : ")
      PT1 (POLAR PT 0 (/ RS (SIN B))))
(IF (EQUAL D DS 1E-5) (PROGN
(SETQ PT2 (POLAR PT ANG (/ RS (SIN B))) PT3 (POLAR PT PI (/ RS (SIN B))))
(COMMAND "PLINE" PT1 PT2 PT3 "")
) (PROGN
(SETQ A (+ A TA) RA (* (SIN A) RS) RB (* (COS A) RS))
(COMMAND "PLINE" PT1 "A")
(SETQ PT2 (POLAR (POLAR PT 0 (/ RB (SIN B))) ANG (/ (- R (SQRT (- (* R R) (* RA RA)))) (SIN B))))
(COMMAND "S" PT2)
(REPEAT 35
  (SETQ A (+ A TA) RA (* (SIN A) RS) RB (/ (* (COS A) RS) (SIN B))
        PT2 (POLAR (POLAR PT 0 RB) ANG (/ (- R (SQRT (- (* R R) (* RA RA)))) (SIN B))))
  (COMMAND PT2)
)
(COMMAND "")
))
(SETVAR "OSMODE" OLDOS)
(SETVAR "CMDECHO" 1)
(PRINC)
)
[/php]

qxlonmsn

zxq0220 发表于 2005-4-24 09:52
写错一个地方，下面是更改后的程序：

(DEFUN C:XGX ()

非常感谢你的分享   但是我发现正交的情况是对的    但是斜交的话相贯线不对    不是90°的时候, 公式应该不一样